# How would you write the balanced chemical equation for the reaction of KHP with NaOH?

$1 , 2 - \left\{H O \left(O = C\right)\right\} \left\{{K}^{+} {\text{^(-)O(O=C)}C_6H_4 + NaOH(aq) rarr 1,2-{Na^(+)""^(-)O(O=C)}{K^(+)}}^{-} O \left(O = C\right)\right\} {C}_{6} {H}_{4} + {H}_{2} O \left(a q\right)$
$\text{KHP=potassium hydrogenpthalate}$
$\text{KHP}$ is the mono-potassium salt of phthalic acid $1 , 2 - {\left\{H O \left(O = C\right)\right\}}_{2} {C}_{6} {H}_{4}$, i.e. benzenedicarboxlic acid.