# Human body temperatures are normally distributed with a mean of 98.20 and a standard deviation of 0.62, how do you find the z-score corresponding to a body temperature of 97.93?

May 17, 2015

All you need to do is take a look at your formula for the z-score, which is :

$z = \frac{\overline{x} - \mu}{\sigma}$

where $\overline{x}$ is your tested mean

$\overline{x} = 97.93$

and $\mu$ is the total mean

$\mu = 98.2$

and $\sigma$ is the standard deviation

$\sigma = 0.62$

so now to find the z-score we just put all our info into the formula.

$z = \frac{97.93 - 98.2}{0.62}$

thus $z \approx - 0.4355$