If 0.900 g of oxalic acid, #H_2C_2O_4# (90.04 g/mol) is completely neutralized with 0.500 M #LiOH#, what volume of lithium hydroxide is required?
Ethandioic acid is diprotic and reacts like this:
This tells us that 1 mole
The no. moles
So the no. moles of LiOH must be 2x this amount:
Concentration = no. moles solute/volume of solution i.e: