Question

If `0°<x<90°`, what is the value of `\frac { 1- \sin ^ { 2} x } { \cos ^ { 2} x } - \frac { 1- \cos ^ { 2} x } { \sin ^ { 2} x }`?

Answer 1

The expression has value `0`.

Explanation:

Let's simplify the expression. We can write `1 - sin^2x` as `cos^2x` and `1 - cos^2x` as `sin^2x`.

`= cos^2x/cos^2x - sin^2x/sin^2x`

`= 1 - 1`

`= 0`

Hopefully this helps!