Question

If `1/3 L` of a gas at room temperature exerts a pressure of `35 kPa` on its container, what pressure will the gas exert if the container's volume changes to `7/4 L`?

Answer 1

`P=20/3 k Pa`

Explanation:

`P_1*V_1=P_2*V_2" Boyle-Mariotte's law"`
`1/3*cancel(35)=P*cancel(7)/4`
`P=4*5/3`
`P=20/3 k Pa`