# If 1 g of water has a volume of 1 mL what would the mass of 1 L of water weigh in kilograms?

Sep 29, 2016

You have specified the density, $\rho$, by these parameters. And we know that $1 \cdot g = {10}^{-} 3 \cdot k g$ or that ${10}^{3} \cdot g = 1 \cdot k g$

#### Explanation:

And $\rho$ $=$ $\text{Unit mass"/"Unit volume}$

Here $\rho$ $=$ $\frac{1 \cdot g}{1 \cdot m L}$ $=$ $1 \cdot g \cdot m {L}^{-} 1$

i.e. $\text{mass}$ $=$ $\text{Volume} \times \rho$ $=$

$1 \cdot \cancel{L} \times {10}^{3} \cdot \cancel{m L} \cdot \cancel{{L}^{-} 1} \times 1 \cdot g \cdot \cancel{m {L}^{-} 1}$

$=$ ${10}^{3} \cdot \cancel{g} \times {10}^{-} 3 \cdot k g \cdot \cancel{{g}^{-} 1}$

$=$ $1 \cdot k g$