If 1 mole of H2 gas was collected under 294.2K and 746.7 mmHg, what volume will it occupy?

1 Answer
Apr 28, 2017

Answer:

Well, #V=(nRT)/P#, and of course, we must choose the appropriate gas constant; #R=0.0821*L*atm*K^-1*mol^-1# is used here.

Explanation:

The key to solving these problems is to recall that #1*atm# of pressure will support a column of mercury that is #760*mm# high. A column of mercury may thus be used to measure pressures up to #1*atm#.

And so #V=(1*molxx0.0821*(L*atm)/(K*mol)xx294.2*K)/((746.7*mm*Hg)/(760*mm*Hg*atm^-1)#

#=??L#. It should be about #25*L#.