Question

If `10/3 L` of a gas at room temperature exerts a pressure of `45 kPa` on its container, what pressure will the gas exert if the container's volume changes to `12/5 L`?

Answer 1

`P_2=62,5 kPa`

Explanation:

`"you can solve using the Boyle-Mariotte's law"`
`P_1*V_1=P_2*V_2`
`cancel(45)*10/cancel(3)=P_2*12/5`
`15*10=P_2*12/5`
`P_2=(5*15*10)/12`
`P_2=62,5 kPa`