If #12 L# of a gas at room temperature exerts a pressure of #5 kPa# on its container, what pressure will the gas exert if the container's volume changes to #2 L#?

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Answer 1 · 2018-03-19T17:16:29

The pressure will be #=30kPa#

Apply Boyle's Law

#"Pressure" xx"Volume"="Constant"# at constant temperature

#P_1V_1=P_2V_2#

The initial pressure is #P_1=5kPa#

The initial volume is #V_1=12L#

The final volume is #V_2=2L#

The final pressure is

#P_2=V_1/V_2*P_1=12/2*5=30kPa#