If #12 L# of a gas at room temperature exerts a pressure of #5 kPa# on its container, what pressure will the gas exert if the container's volume changes to #7 L#?

1 Answer
Mar 3, 2018

Answer:

#8.56kPa#

Explanation:

According to Boyle's law Pressure(#P#) of an ideal gas is inversely proportional to the volume(#V#) at a constant temperature.

We can also state that the product of pressure and volume is constant at a constant temperature.

#PV=k#(some constant)

Now, #12L# of gas exerts a pressure of #5kPa.#

that is, #12*5=k#

#k=60#

Now, #P'=k/(V')# (where, #P'# is the new pressure due to volume #V"#)

#P'=60/7#

#P'=8.56kPa#