If 12 L of a gas at room temperature exerts a pressure of 5 kPa on its container, what pressure will the gas exert if the container's volume changes to 7 L?

1 Answer
Mar 3, 2018

8.56kPa

Explanation:

According to Boyle's law Pressure(P) of an ideal gas is inversely proportional to the volume(V) at a constant temperature.

We can also state that the product of pressure and volume is constant at a constant temperature.

PV=k(some constant)

Now, 12L of gas exerts a pressure of 5kPa.

that is, 12*5=k

k=60

Now, P'=k/(V') (where, P' is the new pressure due to volume V")

P'=60/7

P'=8.56kPa