If 12 L of a gas at room temperature exerts a pressure of 5 kPa on its container, what pressure will the gas exert if the container's volume changes to 7 L?

Mar 3, 2018

$8.56 k P a$

Explanation:

According to Boyle's law Pressure($P$) of an ideal gas is inversely proportional to the volume($V$) at a constant temperature.

We can also state that the product of pressure and volume is constant at a constant temperature.

$P V = k$(some constant)

Now, $12 L$ of gas exerts a pressure of $5 k P a .$

that is, $12 \cdot 5 = k$

$k = 60$

Now, $P ' = \frac{k}{V '}$ (where, $P '$ is the new pressure due to volume V")

$P ' = \frac{60}{7}$

$P ' = 8.56 k P a$