Question

If `13/4 L` of a gas at room temperature exerts a pressure of `16 kPa` on its container, what pressure will the gas exert if the container's volume changes to `9/8 L`?

Answer 1

`P_2=46,2 k Pa`

Explanation:

`P_1*V_1=P_2*V_2`
`16*13/cancel(4)=P2*9/cancel(8)`
`(2*16*13)/9=P_2`
`P_2=46,2 k Pa`