If $\frac{13}{4} L$ $13/4 L$ of a gas at room temperature exerts a pressure of $16 k P a$ $16 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $\frac{9}{8} L$ $9/8 L$ ?

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Answer 1 · 2016-02-15T22:26:24

$P_{2} = 46, 2 k P a$ $P_2=46,2 k Pa$

$P_{1} \cdot V_{1} = P_{2} \cdot V_{2}$ $P_1*V_1=P_2*V_2$
$16*13/cancel(4)=P2*9/cancel(8)$
$(2*16*13)/9=P_2$
$P_2=46,2 k Pa$

If 13/4 L134L13/4 L of a gas at room temperature exerts a pressure of 16 kPa16kPa16 kPa on its container, what pressure will the gas exert if the container's volume changes to 9/8 L98L9/8 L?