Question

If `13/4 L` of a gas at room temperature exerts a pressure of `16 kPa` on its container, what pressure will the gas exert if the container's volume changes to `7/8 L`?

Answer 1

`P_2=59,4" " kPa`

Explanation:

`"we can use the Boyle's law to solve this problem"`
`P_1*V_1=P_2*V_2`
`(16*13)/cancel(4)=P_2*7/cancel(8)`
`P_2=(2*16*13)/7`
`P_2=59,4" " kPa`