Question

If `14/3 L` of a gas at room temperature exerts a pressure of `45 kPa` on its container, what pressure will the gas exert if the container's volume changes to `12/5 L`?

Answer 1

The pressure is `=87.5kPa`

Explanation:

We use Boyle's Law

`P_1V_1=P_2V_2`

`P_1=45kPa`

`V_1=14/3 L`

`V_2=12/5L`

`P_2=(P_1V_1)/V_2=(45*14/3)/(12/5)=87.5kPa`