# If 18 L of a gas at room temperature exerts a pressure of 36 kPa on its container, what pressure will the gas exert if the container's volume changes to 27 L?

Jun 5, 2017

The pressure is $= 24 k P a$

#### Explanation:

We apply Boyle's Law

At constant temperature,

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

The initial pressure is ${P}_{1} = 36 k P a$

The initial volume is ${V}_{1} = 18 L$

The final volume is ${V}_{2} = 27 L$

The final pressure is

${P}_{2} = {V}_{1} / {V}_{2} \cdot {P}_{1}$

$= \frac{18}{27} \cdot 36 = 24 k P a$