Question

If `18 L` of a gas at room temperature exerts a pressure of `36 kPa` on its container, what pressure will the gas exert if the container's volume changes to `27 L`?

Answer 1

The pressure is `=24kPa`

Explanation:

We apply Boyle's Law

At constant temperature,

`P_1V_1=P_2V_2`

The initial pressure is `P_1=36kPa`

The initial volume is `V_1=18L`

The final volume is `V_2=27L`

The final pressure is

`P_2=V_1/V_2*P_1`

`=18/27*36=24kPa`