Question

If `18 L` of a gas at room temperature exerts a pressure of `5 kPa` on its container, what pressure will the gas exert if the container's volume changes to `12 L`?

Answer 1

This a pretty straight forward application of Boyle's Law, expressed by the equation: `P_1V_1 = P_2V_2`
`18*5 = 12*V_2 " solve for " V_2`
`v_2 =5 18/12 = 5 3/2 =15/2 =7.5 kPa`