Question

If `19 L` of a gas at room temperature exerts a pressure of `2 kPa` on its container, what pressure will the gas exert if the container's volume changes to `7 L`?

Answer 1

`P_2=5,43" " kPa`

Explanation:

`"We can use the Boyle's law"`
`P_1*V_1=P_2*V_2`
`2*19=P_2*7`
`P_2=(2*19)/7`

`P_2=38/7`
`P_2=5,43" " kPa`