# If 19 L of a gas at room temperature exerts a pressure of 4 kPa on its container, what pressure will the gas exert if the container's volume changes to 7 L?

May 20, 2017

$11 \cdot {10}^{3} P a$

#### Explanation:

When the containers volume changes to $7 L$ from $19 L$
some work must be done hence from Boyle's law We can say that

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

where $P V = \text{costant}$

so by substituting the values we get

$19 \cdot 4 \cdot {10}^{3} = 7 \cdot {P}_{2}$

${P}_{2} = 10.9 \cdot {10}^{3} \cong 11 \cdot {10}^{3}$