If #2 L# of a gas at room temperature exerts a pressure of #5 kPa# on its container, what pressure will the gas exert if it the container's volume changes to #2/3 L#?

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Answer 1 · 2016-11-15T13:38:48

The pressure is #=15 kPa#

We use Boyle's law

#P_1V_1=P_2V_2#

#P_1=5kPa#

#V_1=2l#

#V_2=2/3l#

The new pressure is

#P_2=(P_1V_1)/V_2=(5*2)/(2/3)=5*2*3/2=15 kPa#