Question

If `24 L` of a gas at room temperature exerts a pressure of `8 kPa` on its container, what pressure will the gas exert if the container's volume changes to `15 L`?

Answer 1

`12.8"kPa"`

Explanation:

`P_1V_1=P_2V_2`

`1L=0.001m^3`

`8000*0.024=0.015P_2`

`P_2=(8000*0.024)/0.015=12800"Pa"=12.8"kPa"`