# If 24 L of a gas at room temperature exerts a pressure of 8 kPa on its container, what pressure will the gas exert if the container's volume changes to 15 L?

Aug 11, 2017

$12.8 \text{kPa}$

#### Explanation:

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

$1 L = 0.001 {m}^{3}$

$8000 \cdot 0.024 = 0.015 {P}_{2}$

${P}_{2} = \frac{8000 \cdot 0.024}{0.015} = 12800 \text{Pa"=12.8"kPa}$