# If 26.03 g of water showed a temperature increase of 102°C upon addition of hot metal, what is the heat change for the water?

Jan 23, 2016

I found $11 k J$

#### Explanation:

I would go for:
$Q = m c \Delta T$
where:
$Q =$ heat gained or lost;
$m =$ mass;
$c =$ heat capacity of the specific material ($4.2 \frac{J}{g K}$ for water);
$\Delta T =$ change in temperature.

$Q = 26.03 \cdot 4.2 \cdot 102 = 11 , 151.2 J \approx 11 k J$