Question

If 26.03 g of water showed a temperature increase of 102°C upon addition of hot metal, what is the heat change for the water?

Answer 1

I found `11kJ`

Explanation:

I would go for:
`Q=mcDeltaT`
where:
`Q=` heat gained or lost;
`m=` mass;
`c=` heat capacity of the specific material (`4.2J/(gK)` for water);
`DeltaT=` change in temperature.

in your case:

`Q=26.03*4.2*102=11,151.2J~~11kJ`