If 26.03 g of water showed a temperature increase of 102°C upon addition of hot metal, what is the heat change for the water?

1 Answer
Jan 23, 2016

Answer:

I found #11kJ#

Explanation:

I would go for:
#Q=mcDeltaT#
where:
#Q=# heat gained or lost;
#m=# mass;
#c=# heat capacity of the specific material (#4.2J/(gK)# for water);
#DeltaT=# change in temperature.

in your case:

#Q=26.03*4.2*102=11,151.2J~~11kJ#