If 3.0 g N reacts with 4.0 g H, given the equation N2(g) + 3 H2(g) → 2 NH3(g), how many grams of ammonia will form and what is the limiting reactant?
Nitrogen is the limiting reactant, and
We have the familiar Haber process equation...
Since the mole ratio of
Here, if we have
So, we would need
But, we have
So, hydrogen is the excess reactant and that therefore makes nitrogen the limiting reactant.
That means, we could only produce so much ammonia with only the nitrogen that we have.
The mole ratio between
Since we have
Ammonia has a molar mass of