If #3 L# of a gas at room temperature exerts a pressure of #5 kPa# on its container, what pressure will the gas exert if it the container's volume changes to #2/3 L#?

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Answer 1 · 2017-03-02T07:53:36

The pressure is #=22.5kPa#

We apply Boyle's Law

#P_1V_1=P_2V_2#

#P_1=5kPa#

#V_1=3L#

#V_2=2/3L#

#P_2=V_1/V_2*P_1#

#=3/(2/3)*5=45/2=22.5kPa#