Question

If `3 L` of a gas at room temperature exerts a pressure of `7 kPa` on its container, what pressure will the gas exert if it the container's volume changes to `2 L`?

Answer 1

`P_2=10,5 k Pa`

Explanation:

`P_1*V_1=P_2*V_2`
`7*3=P_2*2`
`21=2*P_2`
`P_2=21/2`
`P_2=10,5 k Pa`