If #3^n=27#, what is the value of #4^(n-1)#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Alan N. Dec 9, 2016 16 Explanation: #3^n=27# Notice that #27 = 3^3# Hence: #3^n=3^3# Equating exponents:#-> n=3# #:. 4^(n-1) = 4^(3-1)# #=4^2 = 16# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1732 views around the world You can reuse this answer Creative Commons License