Question

If `32 L` of a gas at room temperature exerts a pressure of `6 kPa` on its container, what pressure will the gas exert if the container's volume changes to `8 L`?

Answer 1

`P_2=24kPa`

Explanation:

`P_1=6kPa`
`V_1=32L`
`V_2=8L`
`P_2=?`

`"we can solve using the Boyle's law."`
`P_1*V_1=P_2*V_2`
`6*cancel(32)=P_2*cancel(8)`
`6*4=P_2`
`P_2=24kPa`