If #32 L# of a gas at room temperature exerts a pressure of #6 kPa# on its container, what pressure will the gas exert if the container's volume changes to #2 L#?

1 Answer
Feb 28, 2016

Answer:

96kPa will be the pressure exerted by gas in container, if its volume changes to 2L.

Explanation:

Assume that temperature at two volumes (i.e. 32L and 2L) remains unchanged.

Case i :

#V_1=32L#

#P_1 =6000 Pa#

case ii:

#V_2=2L#

#P_2=?#

we know that

#V_1prop1/(P_1)##------(1)#

#V_2 prop 1/(P_2)##------(2)#

doing #(1)//(2)#

#(V_1)/(V_2)=(P_2)/(P_1)#

substitute given data above equation

#32/2=(P_2)/6000#

#P_2=16xx6000#

#P_2=96000 Pa#