If $32 L$ of a gas at room temperature exerts a pressure of $6 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $2 L$ ?

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Answer 1 · 2016-02-28T09:47:42

96kPa will be the pressure exerted by gas in container, if its volume changes to 2L.

Assume that temperature at two volumes (i.e. 32L and 2L) remains unchanged.

Case i :

$V_1=32L$

$P_1 =6000 Pa$

case ii:

$V_2=2L$

$P_2=?$

we know that

$V_1prop1/(P_1)$ $------(1)$

$V_2 prop 1/(P_2)$ $------(2)$

doing $(1)//(2)$

$(V_1)/(V_2)=(P_2)/(P_1)$

substitute given data above equation

$32/2=(P_2)/6000$

$P_2=16xx6000$

$P_2=96000 Pa$

If 32 L32 L of a gas at room temperature exerts a pressure of 6 kPa6 kPa on its container, what pressure will the gas exert if the container's volume changes to 2 L2 L?