If #32 L# of a gas at room temperature exerts a pressure of #64 kPa# on its container, what pressure will the gas exert if the container's volume changes to #24 L#?

1 Answer
Mar 19, 2016

Answer:

The decrease in volume causes the pressure to increase to 85 kPa.

Explanation:

This is an example of Boyle's law, which states that the pressure and volume of a gas kept at constant temperature vary inversely, meaning that if the volume increases, the pressure will decrease and vice versa. The equation to use is #V_1P_1=V_2P_2#.

Given
#V_1="32 L"#
#P_1="64 kPa"#
#V_2="24 L"#

Unknown
#P_2"#

Solution
Rearrange the equation to isolate #P_2#, substitute the given values into the equation and solve.

#V_1P_1=V_2P_2#

#P_2=(V_1P_1)/(V_2)#

#P_2=((32cancel"L")xx(64"kPa"))/(24cancel"L")#

#P_2="85 kPa"# rounded to two significant figures.

As expected from Boyle's law, when the volume decreased from 32 L to 24 L, the pressure increased from 64 kPa to 85 kPa.