Question

If `4 L` of a gas at room temperature exerts a pressure of `45 kPa` on its container, what pressure will the gas exert if the container's volume changes to `15 L`?

Answer 1

`F=2,25.10^9" "N`

Explanation:

`"We can solve using Boyle's law"`
`P_1*V_1=P_2*V_2`
`45/4=P_2/15`
`P_2*4=45*15`
`P_2=(45*15)/4`
`F=2,25.10^9" "N`