# If 425.0 g of mercury at 25.0 degrees Celsius absorbs .750 Kilo joules of heat energy, what will be it's final temperature?

##### 1 Answer

Jun 1, 2018

#### Explanation:

Use this equation

#"Q = mSΔT"#

Where

#"Q ="# Heat absorbed/released#"m ="# Mass of sample#"S ="# Specific heat of sample (#bb"0.14 J/g°C"# **for mercury**)#"ΔT ="# Change in temperature of sample