If $4 a + 5 b = 21$ $4a+5b=21$ and $5 b - 4 c = 17$ $5b-4c=17$ , what is $a + c$ $a+c$ ?

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Answer 1 · 2016-08-15T02:50:27

$a + c = 1$ $a + c = 1$

$5 b = 17 + 4 c$ $5b = 17 + 4c$

$\Rightarrow 4 a + 17 + 4 c = 21$ $=>4a + 17 + 4c = 21$

$4 a + 4 c = 21 - 17$ $4a + 4c = 21 - 17$

$4 a + 4 c = 4$ $4a + 4c = 4$

$4 (a + c) = 4$ $4(a + c) = 4$

$a + c = \frac{4}{4}$ $a + c = 4/4$

$a + c = 1$ $a + c = 1$

Hopefully this helps!

If 4a+5b=214a+5b=214a+5b=21 and 5b-4c=175b−4c=175b-4c=17, what is a+ca+ca+c?