# If 65.34g piece of tin were to lose 754 Joules of energy in a calorimeter while experiencing a temperature change from 23.9 degrees C to 22.0 degrees C, how would you find its specific heat?

##### 1 Answer

#### Answer:

The values you provided are way off.

#### Explanation:

**SIDE NOTE** *First thing first, the values you provided are very inaccurate. Using these values will produce an impossible result for the specific heat of tin, approximately* *times bigger than what its real value is*.

*WIth this being said, I will assume that the piece of tin lost* *instead of* *The result will not be ideal, but it will be closer to reality*.

The question wants you to determine tin's specific heat.

Before doing any calculation, try to get a clear understanding of what you need to determine.

A substance's *specific heat* tells you the amount of heat needed to increase the temperature of

In your case, a mroe accurate description would sound like this - the amount of heat that must be lost by

The equation that establishes a relationship between heat **lost** and change in temperature looks like this

#color(blue)(-q = m * c * DeltaT)" "# , where

*final temperature* **minus** *initial temperature*

The trick here is to realize that when heat is being **lost** by the system, *negative value*. In this case,

#q = -"75.4 J"#

Since you have all the information you need to find the specific heat of tin, plug in your values in the above equation and solve for

#c = (-q)/(m * DeltaT)#

#c = (-(-"75.4 J"))/("65.34 g" * (22.0 - 23.9)^@"C") = color(green)(0.607"J"/("g" ""^@"C"))#

The actual specific heat of tin is