If #7/4 L# of a gas at room temperature exerts a pressure of #15 kPa# on its container, what pressure will the gas exert if the container's volume changes to #5/3 L#?

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Answer 1 · 2016-04-04T21:35:00

#P_2=15,75 kPa#

#V_1=7/4 L#

#P_1=15kPa#

#V_2=5/3 L#

#P_2=?#

#P_1*V_1=P_2*V_2" Boyle's law"#

#cancel(15)*7/4=P_2*cancel(5)/3#

#21/4=P_2*1/3#

#P_2=(3*21)/4#

#P_2=63/4#

#P_2=15,75 kPa#