If $7/4 L$ of a gas at room temperature exerts a pressure of $16 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $5/12 L$ ?

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Answer 1 · 2016-05-12T12:46:43

$P_2=67.2" "kPa$

$V_1=7/4L$
$P_1=16kPa$
$V_2=5/12L$
$P_2=?$

$P_1*V_1=P_2*V_2" Boyle's law"$

$16*7/cancel(4)=P_2*5/cancel(12)$

$16*7=P_2*5/3$

$P_2=(16*7*3)/5$

$P_2=67.2" "kPa$

If 7/4 L7/4 L of a gas at room temperature exerts a pressure of 16 kPa16 kPa on its container, what pressure will the gas exert if the container's volume changes to 5/12 L5/12 L?