Question

If `7/4 L` of a gas at room temperature exerts a pressure of `16 kPa` on its container, what pressure will the gas exert if the container's volume changes to `5/12 L`?

Answer 1

`P_2=67.2" "kPa`

Explanation:

`V_1=7/4L`
`P_1=16kPa`
`V_2=5/12L`
`P_2=?`

`P_1*V_1=P_2*V_2" Boyle's law"`

`16*7/cancel(4)=P_2*5/cancel(12)`

`16*7=P_2*5/3`

`P_2=(16*7*3)/5`

`P_2=67.2" "kPa`