Question

If `7/5 L` of a gas at room temperature exerts a pressure of `30 kPa` on its container, what pressure will the gas exert if the container's volume changes to `19/12 L`?

Answer 1

`P_l=26,526 k Pa`

Explanation:

`P_i*V_i=P_l*V_l`
`30* 7/5=P_l*19/12`
`P_l=(cancel(30)*7*12)/(cancel(5)*19)`
`P_l=(42*12)/19`
`P_l=26,526 k Pa`