If #7/6 L# of a gas at room temperature exerts a pressure of #9 kPa# on its container, what pressure will the gas exert if the container's volume changes to #5/4 L#?

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Answer 1 · 2017-02-03T08:19:47

The pressure is #=8.4kPa#

We apply Boyle's Law

#P_1V_1=P_2V_2#

#P_1=9kPa#

#V_1=7/6L#

#V_2=5/4L#

#P_2=V_1/V_2*P_1#

#=(7/6)/(5/4)*9=42/5=8.4kPa#