If #8/3 L# of a gas at room temperature exerts a pressure of #30 kPa# on its container, what pressure will the gas exert if the container's volume changes to #7/12 L#?

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Answer 1 · 2016-03-30T06:06:31

#P_2=137,14" " kPa#

#"let's use the Boyle's law"#
#P_1*V_1=P_2*V_2#

#"given values:"#
#P_1=30" " kPa#
#V_1=8/3 " "L#
#V_2=7/12 " "L#

#"asked value:"#
#P_2=?#

#cancel(30)*8/cancel(3)=P_2*7/12#

#10*8=P_2*7/12#

#P_2=(10*8*12)/7#

#P_2=137,14" " kPa#