If #9/4 L# of a gas at room temperature exerts a pressure of #42 kPa# on its container, what pressure will the gas exert if the container's volume changes to #9/7 L#?

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Answer 1 · 2017-02-09T15:44:06

The pressure is #=73.5kPa#

We apply Boyle's Law

#P_1V_1=P_2V_2#

#P_1=42kPa#

#V_1=9/4L#

#V_2=9/7L#

#P_2=V_1/V_2*P_1#

#=(9/4)/(9/7)*42=7/4*42=73.5kPa#