If a #2 kg# object is constantly accelerated from #0m/s# to #15 m/s# over # 12s#, how much power musy be applied at #t= 1 #?

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Mar 8, 2018

Answer:

#"18.75 watts"# is the power constantly applied.

Explanation:

First, find the total energy at the end, in this case kinetic energy

#1/2×"2kg"× ("15 m/s")^2 = "225 joules"#

Then divide #"225 joules"# by the time in seconds to get the average power in watts:

#"225 Joule"/"12 s" = "18.75 watts"#

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