If #A= <4, 9 ,-1 ># and #B= <9 ,-1 ,8 >#, what is #A*B -||A|| ||B||#?

Question

If #A= <4, 9 ,-1 ># and #B= <9 ,-1 ,8 >#, what is #A*B -||A|| ||B||#?

1 Answer

Related questions

How do you write the components of vectors?
How can vectors be represented?
What does the i and j stand for in vectors?
If #\vec{g}# is in standard position with terminal point (5, 5) and #\vec{h}# is in standard...
If #\vec{i}# is in standard position with terminal point (1, 5) and #\vec{j}# is in standard...
How do you find the coordinates of vector PQ in standard position given Points P( 4,5) and Q (-7,3)?
Using (-3, -2) as the initial point, how do you draw the vector that represents the complex...
Using (-3, -2) as the initial point, how do you draw the vector that represents the complex number #8#?
How do you give the complex number form of the vector with the given initial and terminal point...
How do you give the complex number form of the vector with the given initial and terminal point...

Impact of this question

1298 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-20T18:41:37

The answer is #19-sqrt98*sqrt146=#

Explanation:

The dot product is #vecA.vecB=36-9-8=19#
Norm of #∥vecA∥=sqrt(16+81+1)=sqrt(98)#
Norm of #∥vecB∥=sqrt(81+1+64)=sqrt(146)#
So the result is #=vecA.vecB-∥vecA∥*∥vecB∥=19-sqrt98*sqrt146#

Science

Math

Humanities

... and beyond

If #A= <4, 9 ,-1 ># and #B= <9 ,-1 ,8 >#, what is #A*B -||A|| ||B||#?

1 Answer

Explanation:

Related questions

Impact of this question