If a current of #6 A# passing through a circuit generates #12 W# of power, what is the resistance of the circuit?

2 Answers

#1/3\ \Omega#

Explanation:

Power (#P#) of a circuit carrying a current #I# & having a resistance #R# is given as
#P=I^2R#
but given that #I=6A# & power #P=12 W# hence
#12=6^2R#
#R=\frac{12}{36}#
#R=1/3\ \Omega#

Jun 20, 2018

Approximately #0.33# ohms.

Explanation:

Power is related through resistance and current by the equation:

#P=I^2R#

where:

  • #P# is the power in watts

  • #I# is the current in amperes

  • #R# is the resistance in ohms

Rearranging for resistance, we get:

#R=P/I^2#

Now, plugging in our given values, we find that:

#R=(12 \ "W")/(6 \ "A")^2#

#=(12 \ "W")/(36 \ "A"^2)#

#=1/3 \ Omega#

#~~0.33 \ Omega#