If a polynomial function with rational coefficients has the zeros -1, 5, #-2+sqrt5#, what are the additional zeros? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer marfre May 5, 2017 Answer: #-2 - sqrt(5)# Explanation: Complex zeros and radical zeros always come in conjugate pairs: #a+-bi " " and a +- sqrt(b)# The polynomial function is #f(x) = a(x+1)(x-5)(x+2-sqrt(5))(x+2+sqrt(5))#, where #a# is a constant. Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 176 views around the world You can reuse this answer Creative Commons License