# If a projectile is shot at a velocity of 1 m/s and an angle of pi/4, how far will the projectile travel before landing?

Distance travelled horizontally by a projectile i.e the range of a projectile is expressed as $R = \frac{{u}^{2} \sin 2 \theta}{g}$ where, $u$ is the velocity of projection and $\theta$ is the angle of projection.
Given, $u = 1 m {s}^{-} 1 , \theta = {45}^{\circ}$
So,R=(1^2 ×1)/g=0.102m