Question

If a rocket with a mass of `2500` tons vertically accelerates at a rate of `2 m/s^2`, how much power will the rocket have to exert to maintain its acceleration at 3 seconds?

Answer 1

Initial velocity of rocket u = 0m/s
Acceleration `a =2m/s^2`
velocity at 3s =`v=0+2xx3=6m/s`
height at 3 s `h =0xx3+1/2xx2xx3^2=9m`
Total energy supplied up to 3sec = `E=1/2xxmv^2+mxxgxxh=25xx10^5xx(1/2xx6^2+9.8xx9)J`
`=2655xx10^5J`
So
power to exert =`E/t=885xx10^5W=88.5MW`