Question

If a rocket with a mass of 3900 tons vertically accelerates at a rate of `15/8 m/s^2`, how much power will the rocket have to exert to maintain its acceleration at 5 seconds?

Answer 1

`34 × 10^7 color(white)(‘) "Watt"`

Explanation:

Velocity of rocket after 5 seconds is
`v = u + at = 0 + (15/8"m/s"^2 × "5 s") = "9.375 m/s"`

By work energy theorem
Work done by rocket = Kinetic energy gained by it in 5 seconds

`"Power" = "Work"/"Time" = (1/2mv^2)/t`

`= (1/2 × 3900 × 10^3 "kg" × ("9.375 m/s")^2) / "5 s"`

`= 34 × 10^7 color(white)(‘) "Watt"`