# If a rocket with a mass of #700 kg# vertically accelerates at a rate of # 3/2 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 4 seconds?

##### 1 Answer

Jan 29, 2017

P=6.3 KW

#### Explanation:

see

MASS=700 kg

Acceleration=

THEREFORE force exerted is

Now

so by this we can get

therefore

dividing both sides of the equation by

And by definition power is energy per unit time and velocity is displacement per unit time.so applying these