Question

If a spring has a constant of `1 (kg)/s^2`, how much work will it take to extend the spring by `12 cm`?

Answer 1

`W=0,0072J`

Explanation:

`W=E_p=1/2*K*Delta x^2`
`W=1/2*1*(0,12)^2`
`W=(0,0144)/2=0,0072`
`W=0,0072J`