# If a spring has a constant of 12 (kg)/s^2, how much work will it take to extend the spring by 16 cm ?

Oct 2, 2017

Here, spring constant $\frac{\text{k" = 12"kg}}{s} ^ 2$
Displacement $\text{x} = 16 c m = 0.16 m$
Work $= \frac{1}{2} k {x}^{2}$
$= \frac{1}{2} 12 \frac{\text{kg}}{s} ^ 2 \cdot 0.16 m$
$= 0.96 J$