Question

If a spring has a constant of `12 (kg)/s^2`, how much work will it take to extend the spring by `16 cm`?

Answer 1

0.96 J

Explanation:

Here, spring constant `"k" = 12"kg"/s^2`
Displacement `"x"=16cm = 0.16m`

Work `= 1/2 kx^2`
`=1/2 12"kg"/s^2 * 0.16m`
`=0.96 J`