# If a spring has a constant of 15 (kg)/s^2, how much work will it take to extend the spring by 27 cm ?

Mar 4, 2016

${W}_{E} _ p = 0 , 54675 \text{ } J$
$W = {E}_{p} = \frac{1}{2} \cdot k \cdot \Delta {x}^{2}$
$27 c m = 0 , 27 \text{ } m$
$W = {E}_{p} = \frac{1}{2} \cdot 15 \cdot \left(0 , {27}^{2}\right)$
${W}_{E} _ p = 0 , 54675 \text{ } J$