If a spring has a constant of #2 (kg)/s^2#, how much work will it take to extend the spring by #34 cm #?

1 Answer
Aug 15, 2016

Answer:

#E=0.12" "J" rounded to the two decimal place"#

Explanation:

#"Convert 'cm' to 'm'"#
#Delta x=34 " "cm=0.34 " "m#
#K=2" "N/m#

#"we can calculate using the formula "E=1/2*K*Delta x^2#

#E=1/cancel(2)*cancel(2)(0.34)^2#

#E=(0.34)^2#

#E=0.12" "J" rounded to the two decimal place"#