# If a spring has a constant of 2 (kg)/s^2, how much work will it take to extend the spring by 92 cm ?

Jul 14, 2017

The work is $= 0.85 J$

#### Explanation:

The spring constant is $k = 2 k g {s}^{-} 2$

The extension is $x = 0.92 m$

The work is

$W = \frac{1}{2} k {x}^{2}$

$= \frac{1}{2} \cdot 2 \cdot {0.92}^{2}$

$= 0.85 J$