If a spring has a constant of #2 (kg)/s^2#, how much work will it take to extend the spring by #92 cm #?

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Answer 1 · 2017-07-14T15:22:47

The work is #=0.85J#

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The spring constant is #k=2kgs^-2#

The extension is #x=0.92m#

The work is

#W=1/2kx^2#

#=1/2*2*0.92^2#

#=0.85J#